# Calculus: Evaluate the Double Integral

**Evaluate the integral ∫1-2 **∫y-y^2 dxdy **<**– That’s not a typo, there’s no given function to integrate

**Solution: **Start by integrating with x. In this case, it basically means skipping integration and plugging in the bounds as if there were an x variable.

∫1-2 y^2 – y dy

Integrating with y gives us:

(y^3)/3 – (y^2)/2|1-2 => ^{8}⁄_{3} – ^{4}⁄_{2} – (^{1}⁄_{3} – ^{1}⁄_{2})

Simplify this to get:

**Answer: ^{5}⁄_{6}**